34x^2-160x=300

Solution for 34x^2-160x=300 equation:

34x^2-160x=300

We move all terms to the left:

34x^2-160x-(300)=0

a = 34; b = -160; c = -300;
Δ = b2-4ac
Δ = -1602-4·34·(-300)
Δ = 66400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{66400}=\sqrt{400*166}=\sqrt{400}*\sqrt{166}=20\sqrt{166}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-160)-20\sqrt{166}}{2*34}=\frac{160-20\sqrt{166}}{68}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-160)+20\sqrt{166}}{2*34}=\frac{160+20\sqrt{166}}{68}
$